Question

if y = x + log x + log 5 then find dy/dx​

Answer 1

Answer:

dy/dx= d(x+logx+log5)/dx=d(x)/dx+d(logx)/dx+d(log5)/dx= as mentioned 1+1/x+0 which is (x^2+1)/x

Step-by-step explanation:

important formulae for the problem derivative of x with respect to x is 1 and derivative of logx with respect to x is 1/x and derivative of constant with respect to any variable is 0 in the problem we can get a confusion of derivative is log5 like examples as there is a constant in the log the value of the log5 is also constant so the derivative of log5 is also 0 which is with respect to x