Question

if y=x logx
then find dy/dx​

Answer 1

Answer:

dy/dx = 1/x

Step-by-step explanation:

Answer 2

Answer:

1 + logx

Step-by-step explanation:

Given ,

y = x logx

To differentiate or finding dy/dx.

We know that,

• d/dx (uv) = u dv/dx + v du/dx

Therefore, we will get,

=> dy/dx = x d/dx (logx) + logx d/dx(x)

But, we know that,

• d/dx(logx) = 1/x
• d/dx(x) = 1

Therefore, we will get,

=> dy/dx = x(1/x) + logx(1)

=> dy/dx = 1 + logx

Hence, the required value of dy/dx = (1+ logx)