Question

if y= x^n, then yn equal to what ​

Answer 1

Answer:

y=x^n

y^n=(x^n)^n

y^n=x^2n

Answer 2

Given:

$y=x^n$

To find:

$y^n$

Solution:

We have,

$y=x^n$

To find $y^n$, we need to multiply the left-hand side n times or we need to raise it to its $n^{th}$ power.

In the given equation, if we raise the left-hand side to it's $n^{th}$ power, then we need to do the same on the right-hand side. So, we can write,

$(y)^n=(x^n)^n$

Now when we have two powers of a common base as in the case of $x$ here, we add the two powers. So in this case we can write,

$(y)^n=x^{(n+n)}$

⇒$y^n=x^{2n}$

Hence, the required value of $y^n$ is $x^{2n}$.