If y = x^sin x + sin^-1 √x, then find
dy/dx
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Answer:
7ANSWER
y=
1−x
2
xsin
−1
x
y
1−x
2
=xsin
−1
x
Differentiating both sides w.r.to x, we get
y⋅
2
1−x
2
(−2x)
+
1−x
2
dx
dy
=x⋅
1−x
2
1
+sin
−1
x
−xy+(1−x
2
)
dx
dy
=x+
1−x
2
sin
−1
x
−xy+(1−x
2
)
dx
dy
=x+
1−x
2
⋅
x
y
1−x
2
−xy+(1−x
2
)
dx
dy
=x+
x
y
(1−x
2
)
−xy+(1−x
2
)
dx
dy
=x+
x
y
−yx
(1−x
2
)
dx
dy
=x+
x
y
Step-by-step explanation:
hope it will help you
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