Question

If y = x+-, then x4 + x3 - 4x2 + x + 1 = 0
х
becomes
(1) x2(y2 + y - 2) = 0 127 x2(y2 + y - 6) = 0
(3) x?(y2 + y - 3) = 0 (4) x2(y2 + y - 4) = 0
Plss give detailed answer​

Answer 1

Answer:

х

becomes

(1) x2(y2 + y - 2) = 0 127 x2(y2 + y - 6) = 0

(3) x?(y2 + y - 3) = 0 (4) x2(y2 + y - 4) = 0

Plss give detailed answer