if y=x+x^2+x^3+.....infinity
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The R.H.S. of the equation is a sequence in geometric progression with infinite terms, with,
first term, i.e., a = x, and
common ratio, i.e., r = -x
Now, sum of a sequence in geometric progression with infinite terms is given by
S = a/(1-r)
Here, x∈(-1, 1], otherwise the sum of the terms will be infinite.
Therefore,
R.H.S. = x/(1+x)
Now, y = x/(1+x)
⇒ y+xy = x
⇒ y = x(1-y)
⇒ x = y/(1-y) = answer
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Answer:
94000130 FCFD0200 had hi Dr fjdjdj
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