Math, asked by dhruv283, 1 year ago

If y = x + x^2 + x^3 +.........…..+ infinity and |x| < 1 then proove that x = y/1+y​

Answers

Answered by ravihalbharath
2

Answer:

Step-by-step explanation:they gave us that y=x^1+ x^2+ x^3+ .........infinity. Now we can write y=x+ x(x+ x^2+ x^3+.......). Now y=x+x.y but taking x as common y=x(1+y).therefore x=y/(y+1)

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