If y=x^x, Find dy/dx
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f(x) = x^x
f(x + h) = (x^(x + h))
lim [f(x + h) - f(x) ]/h
h->0
lim [ x^(x + h) - x^x ] /h
h->0
lim x^x ( x^h - 1) / h
h ->0
x^x × lim (x^h - 1)/h
h->0
By logrithmic limit limx->0 (a^x - 1)/x = loga
•°• = x^x × logx
f'(x) = x^x × logx
dy/dx = x^x × logx is Answer
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