Question

if y = x/√x find dy/dx=?
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Answer 1

Answer:

We have, y=x

We have, y=x x

We have, y=x x

We have, y=x x Taking log on both the sides, we get

We have, y=x x Taking log on both the sides, we getlogy=xlogx

We have, y=x x Taking log on both the sides, we getlogy=xlogxOn differentiating w.r.t. x, we get

We have, y=x x Taking log on both the sides, we getlogy=xlogxOn differentiating w.r.t. x, we gety

We have, y=x x Taking log on both the sides, we getlogy=xlogxOn differentiating w.r.t. x, we gety1

We have, y=x x Taking log on both the sides, we getlogy=xlogxOn differentiating w.r.t. x, we gety1

We have, y=x x Taking log on both the sides, we getlogy=xlogxOn differentiating w.r.t. x, we gety1

We have, y=x x Taking log on both the sides, we getlogy=xlogxOn differentiating w.r.t. x, we gety1 dx

We have, y=x x Taking log on both the sides, we getlogy=xlogxOn differentiating w.r.t. x, we gety1 dxdd = xx +logx

+logx⇒ dx

+logx⇒ dxdd =y+ylogx

=y+ylogx⇒ dxdy

=y+ylogx⇒ dxdy =x

=y+ylogx⇒ dxdy =x x

=y+ylogx⇒ dxdy =x x (1+logx) ....(∵y=x

=y+ylogx⇒ dxdy =x x (1+logx) ....(∵y=x x

=y+ylogx⇒ dxdy =x x (1+logx) ....(∵y=x x )

Answer 2

Answer:

Step-by-step explanation: