If y = x2 - 2x + 3 then what will be the minimum value of y ?
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Ok cool … So, we have:
y=x2−2x+3y=x2−2x+3
OR,
y=(x-1)^2 + 2
Clearly, (x-1)^2>=0 .
So,
y>=2 .
In the view of Calculus :
Differentiation on both sides yields..
y’=(2x-2)
y’’=2>0 (So, it only has a minima (Upward Concave Parabola) )
Equating it to zero gives x=1 .
Again giving us minimum at x=1 when y=2.
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