Math, asked by navrojkaur617, 23 hours ago

if y =x² then y ,5 is equal to

Answers

Answered by sonysony28050

Answer:

y=x

y=x 2

y=x 2 +

y=x 2 + y

y=x 2 + y1

y=x 2 + y1 ⇒y

y=x 2 + y1 ⇒y 2

y=x 2 + y1 ⇒y 2 =x

y=x 2 + y1 ⇒y 2 =x 2

y=x 2 + y1 ⇒y 2 =x 2 y+1

y=x 2 + y1 ⇒y 2 =x 2 y+1Differentiating both sides

y=x 2 + y1 ⇒y 2 =x 2 y+1Differentiating both sides2y

y=x 2 + y1 ⇒y 2 =x 2 y+1Differentiating both sides2y dx

y=x 2 + y1 ⇒y 2 =x 2 y+1Differentiating both sides2y dxdy

y=x 2 + y1 ⇒y 2 =x 2 y+1Differentiating both sides2y dxdy =2xy+x

y=x 2 + y1 ⇒y 2 =x 2 y+1Differentiating both sides2y dxdy =2xy+x 2

y=x 2 + y1 ⇒y 2 =x 2 y+1Differentiating both sides2y dxdy =2xy+x 2 dx

y=x 2 + y1 ⇒y 2 =x 2 y+1Differentiating both sides2y dxdy =2xy+x 2 dxdy

y=x 2 + y1 ⇒y 2 =x 2 y+1Differentiating both sides2y dxdy =2xy+x 2 dxdy ⇒(2y−x

y=x 2 + y1 ⇒y 2 =x 2 y+1Differentiating both sides2y dxdy =2xy+x 2 dxdy ⇒(2y−x 2

y=x 2 + y1 ⇒y 2 =x 2 y+1Differentiating both sides2y dxdy =2xy+x 2 dxdy ⇒(2y−x 2 )

y=x 2 + y1 ⇒y 2 =x 2 y+1Differentiating both sides2y dxdy =2xy+x 2 dxdy ⇒(2y−x 2 ) dx

y=x 2 + y1 ⇒y 2 =x 2 y+1Differentiating both sides2y dxdy =2xy+x 2 dxdy ⇒(2y−x 2 ) dxdy

y=x 2 + y1 ⇒y 2 =x 2 y+1Differentiating both sides2y dxdy =2xy+x 2 dxdy ⇒(2y−x 2 ) dxdy =2xy

y=x 2 + y1 ⇒y 2 =x 2 y+1Differentiating both sides2y dxdy =2xy+x 2 dxdy ⇒(2y−x 2 ) dxdy =2xy⇒

y=x 2 + y1 ⇒y 2 =x 2 y+1Differentiating both sides2y dxdy =2xy+x 2 dxdy ⇒(2y−x 2 ) dxdy =2xy⇒ dx

y=x 2 + y1 ⇒y 2 =x 2 y+1Differentiating both sides2y dxdy =2xy+x 2 dxdy ⇒(2y−x 2 ) dxdy =2xy⇒ dxdy

y=x 2 + y1 ⇒y 2 =x 2 y+1Differentiating both sides2y dxdy =2xy+x 2 dxdy ⇒(2y−x 2 ) dxdy =2xy⇒ dxdy =

y=x 2 + y1 ⇒y 2 =x 2 y+1Differentiating both sides2y dxdy =2xy+x 2 dxdy ⇒(2y−x 2 ) dxdy =2xy⇒ dxdy = 2y−x

y=x 2 + y1 ⇒y 2 =x 2 y+1Differentiating both sides2y dxdy =2xy+x 2 dxdy ⇒(2y−x 2 ) dxdy =2xy⇒ dxdy = 2y−x 2

y=x 2 + y1 ⇒y 2 =x 2 y+1Differentiating both sides2y dxdy =2xy+x 2 dxdy ⇒(2y−x 2 ) dxdy =2xy⇒ dxdy = 2y−x 2 2xy

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