If y = x³✓2+3x/
(1-x) (2 + x)
then find dy/dx
Answers
Answered by
0
Answer:
put x=tanθ⇒θ=tan
−1
x
y=tan
−1
[
1−3tan
2
θ
3tanθ−tan
3
θ
]
y=tan
−1
[tan3θ]
y=3θ=3(tan
−1
x)
Diff. on both sides.
dx
dy
=3.
dx
d(tan
−1
x)
=
1+x
2
3
[(tan
−1
x)
1
=
1+x
2
Step-by-step explanation:
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Answered by
0
Answer:
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bro
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