if y=x3.logx them find dy/dx
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Answered by
5
given
y = x^3logx
differentiating with respect to x we get
dy/dx= 3x^2logx + x^2
Answered by
9
given
y = x^3logx
differentiating with respect to x we get
dy/dx= 3x^2logx + x^2
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