If y=xcosy+ycosx find dx/dy
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xcosy((cosy)/x−y′(siny)(lnx))+ycosx((cosx)y′/y−(sinx)(lny))=0
xcosy((cosy)/x−y′(siny)(lnx))+ycosx((cosx)y′/y−(sinx)(lny))=0.
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