if y=xlogy prove that dy÷dx= ysquare÷x(y-x)
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proved
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If y=xlogy prove that dy÷dx= ysquare÷x(y-x)
If y=xlogy prove that dy÷dx= y²÷x(y-x)
y=xlogy
y' = logy + xy'/y
y'(1-x/y) = logy = y/x
y'(y-x)/y = y/x
y'(y-x) = y²/x
y' = y²÷ x(y-x)
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