If y=xsinx2,then the value of dy/dx is
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Answer:
sinxcosx
Explanation
= (1)x⁰{sin(2x)} [∵ = xⁿ = nxⁿ⁻¹]
=1×sin2x
= sinxcosx
Ankursoni2002:
It's wrong. In the book the answer is sinx^2+2x^2cosx^2
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