If y+ z = 12 and y*z=30 then what will be the value of y^2 + z^2
Answers
Answered by
0
We have,
(y+z)=12
(y+z)^2=(12)^2 (squaring both sides)
y^2+z^2+2yz=144
y^2+z^2+2(30)=144
y^2+z^2+60=144
y^2+z^2=144-60
y^2+z^2=84 Ans.
(y+z)=12
(y+z)^2=(12)^2 (squaring both sides)
y^2+z^2+2yz=144
y^2+z^2+2(30)=144
y^2+z^2+60=144
y^2+z^2=144-60
y^2+z^2=84 Ans.
Answered by
5
Hey! ! !
Solution :-
☆ Given :-
● y+ z = 12
● y*z=30
:- ( y + z )^2 = y^2 + z^2 + 2(yz)
=> y^2 + z^2 = ( y + z )^2 - 2(yz)
=> y^2 + z^2 = (12)^2 - 2 (30)
=> y^2 + z^2 = 144 - 60
=> y^2 + z^2 = 84
☆ ☆ ☆ Hop its helpful ☆ ☆ ☆
☆ Regards :- ♡♡《 Nitish kr singh 》♡♡
Solution :-
☆ Given :-
● y+ z = 12
● y*z=30
:- ( y + z )^2 = y^2 + z^2 + 2(yz)
=> y^2 + z^2 = ( y + z )^2 - 2(yz)
=> y^2 + z^2 = (12)^2 - 2 (30)
=> y^2 + z^2 = 144 - 60
=> y^2 + z^2 = 84
☆ ☆ ☆ Hop its helpful ☆ ☆ ☆
☆ Regards :- ♡♡《 Nitish kr singh 》♡♡
Similar questions