Question

if ×+y+z=6 ×y+yz+z×=11 find the value ײ+y²+z²​

Answer 1

Answer:

93x

Step-by-step explanation:

646-1/676595-5*91*8

Answer 2

Answer:

(x+y+z)²= x²+y²+z² +2(xy +yz+zx)

x²+y²+z²= 6²-2(11)

= 36-22

=14

Step-by-step explanation:

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