if ×+y+z=6 ×y+yz+z×=11 find the value ײ+y²+z²
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Answered by
0
Answer:
93x
Step-by-step explanation:
646-1/676595-5*91*8
Answered by
0
Answer:
(x+y+z)²= x²+y²+z² +2(xy +yz+zx)
x²+y²+z²= 6²-2(11)
= 36-22
=14
Step-by-step explanation:
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