Question

If (y+z)⅓+(z+x)⅓+(x+y)⅓ = 0 show that (x+y+z)³=9(x³ +y³ +z³).​

Answer 1

Step-by-step explanation:

it can be simply done by assuming y+z^1/3 as a, z+x^1/3 as b and x+y^1/3 as c. Now the formula to be used is : if a+b+c=0, then a^3+b^3+c^3=3×a×b×c. just substitute the values now