Math, asked by shiv3975, 20 days ago

if y²+1/y²=11 find the value of y1/y

Answers

Answered by Salmonpanna2022
2

$\fbox{${{y}\mathrm{{-}}\frac{1}{y}\mathrm{{=}}{3}\hspace{0.33em}\hspace{0.33em}{Ans}{\mathrm{.}}}$}$

Step-by-step explanation:

Question:

if \:  \:  {y }^{2}  \times   \frac{1}{ {y}^{2} }  = 11 \:  \: find \: the \: value \: of \: y  - \frac{1}{y}

Solution:

(y -  \frac{1}{y} )^{2}  =  {y}^{2}  +  \frac{1}{ {y}^{2} }  - 2 \\

$\fbox{${{\mathrm{[.}}{\mathrm{.}}\hspace{0.33em}{\mathrm{(}}{a}\mathrm{{+}}{b}{\mathrm{)}}^{2}\mathrm{{=}}{a}^{2}\mathrm{{+}}{b}^{2}\mathrm{{-}}{2}{ab}}$}$

=11-2

[°.° +1/ = 11 (Given)]

=9

y-1/y = √9 => 3 Ans.

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