Question

If y2 – 2y – 3 = 0, find values of y.

Answer 1

Answer:

y²-2y-3=0

y²+y-3y-3=0

y(y+1)-3(y+1)=0

(y+1) (y-3)= 0

y=-1,+3

Step-by-step explanation:

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Answer 2

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y²-2y-3 = 0

y² +y -3y-3

(y² +y )  ( -3y-3)

y(y+1)   -3( y +1)

(y+1) (y - 3) = 0

y +1 =0        y -3 = 0

y = -1              y = 3

y = -1,3

if we subsuit both values we get answer as zero

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