Question

. If y97 + 97 is divided by y + 1, the remainder is:

Answer 1

Answer:

Step-by-step explanation:

Hope it helps you

Answer 2

The remainder is 96

Given :

$\sf \: The \: polynomial \: \: {y}^{97} + 97$

To find :

The remainder when divided by y + 1

Solution :

Step 1 of 2 :

Find zero of the polynomial y + 1

For Zero of the polynomial y + 1

We have

y + 1 = 0

⇒ y = - 1

Step 2 of 2 :

Find the remainder

$\sf \: Let\: \:f(y) = {y}^{97} + 97$

By Remainder Theorem the required Remainder when f(y) is divided by y + 1 is

= f( - 1)

$\sf = {( - 1)}^{97} + 97$

$\sf = - 1 + 97$

$\sf = 96$

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ Find the remainder when x³-ax²+6x-a is divided by x - a.

https://brainly.in/question/5714646

2. If polynomial 3x^3 – 2x^2 + 4x + 1 is divided by x - 2, then remainder is

https://brainly.in/question/31996931