Question

if y97 +97 is divided by y+1 then the remainder is ​

Answer 1

By remainder theorem, we use the root of y+1=0.

$y+1=0$

$y=-1$

Now substitute -1 into the given dividend.

$(-1)^{97}+97=(-1)+97=96$

Therefore the remainder is 96.

Answer 2

The remainder is 96

Given :

y⁹⁷ + 97 is divided by y + 1

To find :

The remainder

Solution :

Step 1 of 3 :

Write down the given polynomials

Here the given polynomials are

P(y) = y⁹⁷ + 97

Q(y) = y + 1

Step 2 of 3 :

Find zero of Q(y)

For Zero of Q(y) we have

Q(y) = 0

⇒ y + 1 = 0

⇒ y = - 1

Step 3 of 3 :

Find the remainder

By Remainder Theorem the required Remainder when P(y) is Q(y) is

$\sf = P( - 1)$

$\sf = {( - 1)}^{97} + 97$

$\sf = - 1 + 97$

$\sf = 96$

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ Find the remainder when x³-ax²+6x-a is divided by x - a.

https://brainly.in/question/5714646

2. If polynomial 3x^3 – 2x^2 + 4x + 1 is divided by x - 2, then remainder is

https://brainly.in/question/31996931