Question

if you add 10% of a number to itself what percent of the new number should be subtracted to get the original number back

Answer 1

Answer:

Step-by-step explanation:

let the original number be x

so,new number will be x+x/10=11x/10

now,let y= change in new number

so,11x/10-y=x

on rearranging,

y=0.1x

now y%=0.1x/1.1x ×100=100/11%=9.09%

Answer 2

Answer:

Step-by-step explanation:

10%x + x = 0.1x + x = 1.1x

1.1x - y% of 1.1x = x

1.1x - x = y% of 1.1x

0.1x = y% of 1.1x

0.1x = y%(1.1x)

y% = 0.1x / 1.1x = 0.1 / 1.1 = 1 / 11

y/100 = 1 / 11

y = 100 / 11

y = 9.091.

thus 9.091% of 1.1x should be subtracted from 1.1x to get x.