Math, asked by priyanshu406249, 10 months ago

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Answers

Answered by tanika
0

Answer:

Step-by-step explanation:

(1)1/x-1/y=1------------1

1/x+1/y=7-----------2

taking 1/x=p and 1/y=q

∴eq 1= p-q =1--------3

also eq 2 =p+q=7--------4

adding 3 and 4

p+q+p-q=7+1

2p=8

p=4

1/x=4

x=1/4

substituin x in eq 1

1/1/4-1/y=1

4-1/y=1

-1/y=1-4

-1/y=-3

1/y=3

y=1/3

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(2)  Answer:

x = 1/2 , y = 1/3

Solution:

Given Equations Reducible to a Pair of Linear Equations in two variables :

2/x + 3/y = 13 ----(1)

5/x - 4/y = -2 ------(2)

If we substitute 1/x = a and 1/y = b , we get the following pair of linear equations:

2a+3b=13 -----(3)

5a-4b = -2 -----(4)

Coefficients of b are 3 and 4 and

their LCM is 12 .

Using the elimination method .

Equation (3) × 4 8a+12b=52

Equation (4) × 3 15a-12b=-6

'b' terms have opposite sign , so we add the two equations.

23a = 46

=> a = 46/23

=> a = 2

Substitute the value of a in equation (3), we get

=> 2×2 +3b =13

=> 4 + 3b = 13

=> 3b = 13 - 4

=> 3b = 9

=> b = 9/3

=> b = 3

But 1/x = a = 2 => x = 1/2

1/y = b = 3 => y = 1/3

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