Question

if you answer this. I will mark you the brainliest
​

Answer 1

Answer:

2142 cm^2

Step-by-step explanation:

l=42,b=84

Area of rectangle=L×B

=42×84

=3528cm^2

Given, Diameter of semicircle= 42cm

radius= 42/2

r=21cm

area of semi circle= πr^2/2

=(22/7×21×21)2

=1386/2

area of both semicircle= 693cm^2 ×2

=1386 cm^2

shaded area=area of rectangle - area of semicircles

=3528-1386

=2142cm^2

Answer 2

Step-by-step explanation:

$\huge\bf\underline\green{answer}$

$\huge\sf\underline\purple{given:}$

length of rectangle=84cm

breadth of rectangle=42cm

radius.of semicircle=42cm/2=21cm

$\huge\bf\underline\red{to find}$

area of shaded region

$\huge\sf\underline\pink{formula}$

$area \: of \: shaded \: region = area \: of \: rectangle - area \: of \: unshaded \: region$

$\huge\sf\underline\purple{explanation}$

to find area of shaded region we need to do,

area of rectangle-area of unshaded region.

.:unshaded region is iN the form of semicircle.

so,area of semicircle=πr^2/2

solution,

area of shaded region=

=(l×b)-πr^2/2

=(84cm×42cm)-2[(22/7×21×21/2)]

=(3528cm^2)-2(11×3×21)

=3528cm^2-2(693cm^2)

=2835cm^2-693cm^2

.: area of unshaded region is 2142cm^2