Math, asked by anakhaajith, 7 months ago

if you answer this question correctly god will make your day better plz help...​

Attachments:

Answers

Answered by TheBox
0

Answer:

look I have sent the photo

Step-by-step explanation:

look factorize 63 and 28 as 9 × 7 and 4 × 7 now as you know √ab = √a.√b and further solve...

Attachments:
Answered by Mihir1001
0

Answer:

4 \sqrt{7}

Step-by-step explanation:

We have,

 {63}^{1/2}  - 5 \times {(28)}^{1/2}  + 11 \times  {(7)}^{1/2}

 =  \sqrt{63}  - 5 \sqrt{28}  + 11 \sqrt{7}

 =  \sqrt{9 \times 7}  - 5 \sqrt{4 \times 7}  + 11 \sqrt{7}

 =  \sqrt{3 \times 3 \times 7}  - 5 \sqrt{2 \times 2 \times 7}  + 11 \sqrt{7}

 =  \sqrt{ {(3)}^{2}  \times 7}  - 5 \sqrt{ {(2)}^{2}  \times 7}  + 11 \sqrt{7}

 = 3 \sqrt{7}  - (5)2 \sqrt{7}  + 11 \sqrt{7}

 = 3 \sqrt{7}  - 10 \sqrt{7}  + 11 \sqrt{7}

 = (3 - 10 + 11) \sqrt{7}

 = (14 - 10) \sqrt{7}

 = (4) \sqrt{7}

 = 4 \sqrt{7}

.

.

.

.

hope... it helps you

.

.

.

.

.

.

.

mark this answer as BRAINLIEST.

Similar questions