Question

If you apply a net force of 3 N on. 1 kg box what is the acceleration of the box

Answer 1

▶ Solution :

Given :

→ Net force on the box = 3N

→ Mass of the box = 1kg

To Find :

→ Acceleration of the block.

Concept :

→ This question is completely based on Newton's second law of motion.

→ As per Newton's second law of motion, net force on the object is defined as product of mass and acceleration.

→ Mathematically,

$\underline{\boxed{\bf{\pink{F=m\times a}}}}$

• F denotes net force
• m denotes mass
• a denotes acceleration

→ Force is a vector quantity.

→ It has both magnitude as well as direction.

Calculation :

$\leadsto\bf\:F=m\times a\\ \\ \leadsto\sf\:3=1\times a\\ \\ \leadsto\boxed{\bf{\orange{a=3\:ms^{-2}}}}$

Answer 2

${\purple{\underline{\underline{\bf{\pink{Solution:-}}}}}}$

$\mathfrak{\underline{AnswEr:-}}$

• The acceleration of the box = 3 m/s²

$\mathfrak{\underline{Given:-}}$

• The given force is 3N.
• The given mass is 1 kg.

$\mathfrak{\underline{Need\:To\: Find:-}}$

• The acceleration of the box = ?

${\purple{\underline{\underline{\bf{\pink{Explanation:-}}}}}}$

$\:\:\:\:\dag\bf{\underline \green{Formula\:used\:here:-}}$

$\star\: \: {\boxed{\sf\purple{Force = Mass \times Acceleration}}}$

$\:\:\:\:\dag\bf{\underline \blue{Putting\:the\:values:-}}$

$\longrightarrow \sf {3 = 1 \times a}$

$\longrightarrow \sf {a = \dfrac{\cancel{3}}{\cancel{1}}\:}$

$\longrightarrow \sf {a = 3m/s^2}$

$\:\:\:\:\dag\bf{\underline{\underline \red{Hence:-}}}$

• The acceleration of the box is 3 m/s².

$\rule{200}{2}$