Question

. If you apply a net force of 3 N on 100 g-box, what is the acceleration of the box?
A: 5 m/s2
B: 10 m/s2
C: 20 m/s2
D: 30 m/s2

Answer 1

Newton's second law says that the net force on an object is equal to the mass of the object and resulting acceleration. 

F=ma 

Therefore: 

a=F/m= 3 N / .1 kg = 30 meters per second per second.

Answer 2

Answer:

Acceleration of the box, $a=30\ m/s^2$

Explanation:

It is given that,

Net force acting on the box, F = 3 N

Mass of the box, m = 100 g = 0.1 kg

Let a is the acceleration of the box. It can be calculated using the second law of Newton as :

F = ma

$a=\dfrac{F}{m}$

$a=\dfrac{3\ N}{0.1\ kg}$

$a=30\ m/s^2$

So, the acceleration of the box is $30\ m/s^2$. Hence, this is the required solution.