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As per angle sum property of a quadrilateral
Angle A +Angle B +Angle C +Angle D = 360
Here, <A +<C =180°
2x +4+4y-4 =180
2x +4y =180
X +2y = 90...........(1)
< B +<D =180°
x+10 +5y +5 =180
X+5y =180 - 15
X +5y = 165.......(2)
Solving (1) and (2) by elimination method
X +5y =165
X +2y =90
- - -
_____________
3y = 75
Y =75/3
Y =25
From (1)
X +2y =90
X + 2(25) =90
X + 50 =90
X = 90 - 50
X =40
So, we get x =40° and y = 25°
So, <A =(2(40) +4)
= 84°
<B = 40 + 10 =50°
<c = 4(25) - 4
= 100 - 4 = 96°
<D = 5(25) +5
=130°
<A +<B+<C +<D=360°
84 +50 +96 +130 =360
360 = 360
Hence, verified
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