if you are a genius than solve it :.
2-2×3+3=???
Answers
Answered by
1
Answer:
answer is
2-2×3+3
0×6
0
Answered by
3
Method used :— ![\bf\green{\underline{\fbox{\red{BODMAS}}}} \bf\green{\underline{\fbox{\red{BODMAS}}}}](https://tex.z-dn.net/?f=%5Cbf%5Cgreen%7B%5Cunderline%7B%5Cfbox%7B%5Cred%7BBODMAS%7D%7D%7D%7D)
We have,
![\red{ \longmapsto }2 - 2 \times 3 + 3 \red{ \longmapsto }2 - 2 \times 3 + 3](https://tex.z-dn.net/?f=%5Cred%7B+%5Clongmapsto+%7D2+-+2+%5Ctimes+3+%2B+3)
![\orange{ = }2 - (2 \times 3) + 3 \orange{ = }2 - (2 \times 3) + 3](https://tex.z-dn.net/?f=%5Corange%7B+%3D+%7D2+-+%282+%5Ctimes+3%29+%2B+3)
![\orange{ = }2 - 6 + 3 \orange{ = }2 - 6 + 3](https://tex.z-dn.net/?f=%5Corange%7B+%3D+%7D2+-+6+%2B+3)
![\orange{ = }(2 + 3) - 6 \orange{ = }(2 + 3) - 6](https://tex.z-dn.net/?f=%5Corange%7B+%3D+%7D%282+%2B+3%29+-+6)
![\orange{ = }5 - 6 \orange{ = }5 - 6](https://tex.z-dn.net/?f=%5Corange%7B+%3D+%7D5+-+6)
![\orange{ = } - 1 \orange{ = } - 1](https://tex.z-dn.net/?f=%5Corange%7B+%3D+%7D+-+1)
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We have,
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I hope that .........this answer would help you the best.
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please........mark this answer as
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