if you are geneius solve it
given (2,5) (-4,6) and (2,-2) are three vertices of triangle.then find centre of circle which passes through above three vertices
Answers
Answered by
2
Here, [(x1+x2+x3) /3,(y1+y2+y3)/3]
=[(2-4+2)/3,(5+6-2)/3]
=(0/3,9/3)
=(0, 3)
Need not to thank or mark as brainliest, just I hope that it helps you...
=[(2-4+2)/3,(5+6-2)/3]
=(0/3,9/3)
=(0, 3)
Need not to thank or mark as brainliest, just I hope that it helps you...
shoyebahmedknrp6m4gm:
Not helpful at all
is this right or wrong ?
it's absolutely fine.
I considered the three vertices as (x1, y1), (x2, y2), (x3, y3)
and used the formulae.
is that the formula for a centroid ?
yep, it is..
it must be right then
it's right, dude, I am sure.
Similar questions