Question

if you are going on road at 60 degree there is plane the distance of plane from u is 289 km find distance bw plane and surface​

Answer 1

Answer:

here is the correct answer please mark me brainliest and give thanks

Answer 2

Answer:

Let A is an aeroplane when it is flying at height 4000m from Ground passes vertical above another Aeroplane B at an instant angle of elevation of two planes from same point D on the ground are 60° and 45° respectively as shown in figure , here distance between two planes is AB = h

And distance between point D and C is x { Let }

Now, from ∆ACD ,

tan60° = perpendicular/base =4000/x

x = 4000/tan60° = 4000/√3 m ---(1)

Again, from ∆BCD ,

tan45° = BC/CD = (4000 - h)/x

1 =(4000 - h)/(4000/√3) [ from equation (1)]

4000/√3 = 4000 - h

h = 4000( 1 - 1/√3) m

Hence, distance between two planes is 1690.59 m

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