Question

If you are intelligent then tell me my this questions if you don't know then please don't write anything in answer......
2^2002-2^1996-2^1992-2^1991=k*2^1991.
now tell me the value of k ....

Answer 1

Hi ,

1 ) 2^2002=2^(1991 + 11)=2^1991 ×2^11

2 ) 2^1996 = 2^1991 × 2^5

3) 2^1992 = 2^1991 × 2

Now ,

according to the problem given,

2^ 2002 - 2^1996 - 2^1992 - 2^1991

= k × 2^1991

2^1991×2^11-2^1991×2^5-2^1991×2-

2^1991 = k × 2^1991

2^1991[ 2^11 - 2^5 - 2 - 1 ] = k ×2^1991

After cancellation of 2^1991 both

sides

k = 2^11 - 2^5 - 2 - 1

k = 2048 - 32 - 2 - 1

k = 2048 - 35

k = 2013

I hope this helps you.

:)