Question

if you are travelling in a cab there are fixed charges initially then it is increased by 5 rupees subsequently how can find total fare for 10 km? in arithmetic progression​

Answer 1

Step-by-step explanation:

Taxi fare for first kilometer = Rs. 8

Taxi fare for subsequent distance = Rs. 5

Total distance covered = x

Total fare = Y Since the fare for first kilometer = Rs.8

According to problem,

Fare for (x-1) kilometer = 5(x - 1)

So, the total fare y = 5(x-1) +8

⇒ y = 5(x-1) + 8 ⇒ y = 5x-5+8

⇒ y = 5x + 3

Hence, y = 5x +3

is the required linear equation.

Now the equation is

y = 5x + 3 ...(1)

Now, putting the value x = 0 in (1)

y = 5 x 0+3 y = 0+3=3 So the solution is (0, 3)

Putting the value x 1 in (1)

y = 5 x 1+3 y = 5 + 3 = 8. So the solution is (1,8)

Putting the value x = y = 5x2+3

y = 10 + 3 = 13. So the solution is (2, 13)