if you burn 20.8g of hydrogen and produce 186g of water,ho much oxygen reacte
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So if we find the moles of each: H2 (20.8/1 = 20.8mol) H2O (186/18 = 10.33)
the equation is: 2H2 + O2 ===> 2H2O
its a 2:2 ratio between h2 and h20 so we use the limiting moles which is 10.33
to find mass: mass = moles x RFM
Mass = 10.33 x 32 = 330.56 then since its a 2:1:2 divide by two
mass = 165.28g
the equation is: 2H2 + O2 ===> 2H2O
its a 2:2 ratio between h2 and h20 so we use the limiting moles which is 10.33
to find mass: mass = moles x RFM
Mass = 10.33 x 32 = 330.56 then since its a 2:1:2 divide by two
mass = 165.28g
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