Question

if you can help me i will give you 100 points,so please help me ​

Answer 1

$\huge\underbrace\mathfrak{Answer}$

Given:-

• ABCD is a Quadrilateral
• ∠A= 48° +x
• ∠D= 4x
• ∠C= 3x
• ∠B= 4x

To Find:-

The Value of

• x
• ∠ABC
• ∠ACD

Solution:-

1) For x:-

$∠A+∠B+∠C+∠D = 360\degree$

$→(48 + x) + 4x + 3x + 4x = 360$

$→48 + 12x = 360$

$→12x = 360 - 48$

$→12x = 312$

$→x = \frac{312}{12}$

$→x = 12$

2) for ∠ ABC:-

$4x = 4 \times 12 = 48\degree$

3) For ∠ACD:-

$48 + 4x + ∠acd = 180$

$→\: ∠ACD + 4x + 48 = 180$

$→∠ACD + 4x = 180 - 48$

$→\: ∠ACD + 4 \times 12 = 132$

$→\: ∠ACD = 132 - 48$

$→\: ∠ACD = 84\degree$

Answer 2

Step-by-step explanation:

lFor ∠ACD:-

48 + 4x + ∠acd = 18048+4x+∠acd=180

→\: ∠ACD + 4x + 48 = 180→∠ACD+4x+48=180

→∠ACD + 4x = 180 - 48→∠ACD+4x=180−48

→\: ∠ACD + 4 \times 12 = 132→