If you can, the answer this question. This question was asked in USA Talent Olympiad. see, the pinned image. actually,I was selected in that Olympiad and I won silver medal.
I challenge all class 11 and 12 physics toppers...
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1
Answer:
Given, u=50km/hr=50×
18
5
=
18
250
m/s
v=0
s=6m(at least)
By third equation by motion,
v
2
=u
2
+2as
0=(
18
250
×
18
250
)+2(−a)(s)
0=192.90−12a
a=
12
192.90
=16.07
Now applying third equation of motion,
v
2
=u
2
+2as
⟹0=(100×
18
5
)
2
+2(−16.07)(s)
⟹0=771.60−32.14s
⟹s=
32.14
771.60
=24.00
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