Question

if you can then plz answer this question .

it will be a great help for me .

tomorrow is my exam so olz as soon as possible plz answer this question .
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Answer 1

Answer:

i think it may help you !! Good luck for your exam

Given p=2−a

to prove a3+6ap+p3−8=0...(1)

Now put the value of P in eq (1)

a3+6a(2−a)+(2−a)3−8=0

⇒a3+12a−6a2+8−a3−12a+6a2−8=0

[∴(a−b)3=a3−b3−3a2b+3ab2]

⇒0=0 (By eliminating equal terms we 

have LHS = RHS)