Question

if you divide 555 into three parts such that the second part is one fourth of the third part and the ratio between the first and third part is 3 is to 5 find the each part ​

Answer 1

Answer:

180;75;300.

Step-by-step explanation:

$Let \: the \: third \: part \: be \: c \\ then \: second \: part \: will \: be \: \frac{c}{4} \\ and \: given \: that \: ratio \: of \: first \: and \: third \: part \: = 3 :\: 5 \\ So \: the \: third \: part \: is \: assumed \: as \: 5x \\ According \: to \: the \: problem \\ 3x + \frac{5x}{4} + 5x = 555 \\ \frac{12x + 5x + 20x}{4} = 555 \\ 37x = 555 \times 4 \\ 37x = 2220 \\ x = \frac{2220}{37} \\ x = 60 \\ therefore \: the \: three \: numbers \: are \: 300 (3 {rd)}^{} ;\: \\ 75 (2nd \: )\: and \: 180(1st).$

Answer 2

Answer:

Letthethirdpartbec

thensecondpartwillbe

4

c

andgiventhatratiooffirstandthirdpart=3:5

Sothethirdpartisassumedas5x

Accordingtotheproblem

3x+

4

5x

+5x=555

4

12x+5x+20x

=555

37x=555×4

37x=2220

x=

37

2220

x=60

thereforethethreenumbersare300(3rd)

;

75(2nd)and180(1st).