If you divide the total distance travelled on a car trip by the time for the trip,are you calculating the average speed or magnitude of the average velocity? Under what circumstances are the two quantities are same? illustrate with the help of an example.
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Answered by
91
IF IT IS DISTANCE YOU ARE CALCULATING AVERAGE SPEED,IF IT IS DISPLACEMENT IT IS AVERAGE VELOCITY.IF THE MOTION IS THROUGH A STRAIGHT LINE WE CAN SAY IT AS AVERAGE VELOCITY OR SPEED. EG: IF YOU ARE TRAVELING A DISTANCE OF 60 M AND RETURNING BACK .IF THE TIME TAKEN TO GET THERE IS 2 S
TIME =2*2=4S
THE AVERAGE SPEED=120/4=30.
AVERAGE VELOCITY =0/4=0.
TIME =2*2=4S
THE AVERAGE SPEED=120/4=30.
AVERAGE VELOCITY =0/4=0.
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Answered by
71
If you divide the total distance travelled on a car trip by the time for the trip, then you are calculating average speed.
Average velocity is given by displacement divided by time taken. So magnitude of average velocity will be equal to average speed only when displacement of the object is equal to the distance travelled by the object. And it happens when the object moves in a straight line in one direction only.
For example, Let's say point B is 10m north to Point A in a straight line. If you are travelling along the straight path from point A to point B, then your displacement is same as your distance travelled, that is 10m. So in this case your average speed and magnitude of average velocity will be same.
Average velocity is given by displacement divided by time taken. So magnitude of average velocity will be equal to average speed only when displacement of the object is equal to the distance travelled by the object. And it happens when the object moves in a straight line in one direction only.
For example, Let's say point B is 10m north to Point A in a straight line. If you are travelling along the straight path from point A to point B, then your displacement is same as your distance travelled, that is 10m. So in this case your average speed and magnitude of average velocity will be same.
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