Physics, asked by mishrapinku000, 7 months ago

If you drop a ball and it reaches the ground with velocity 98 m/s in 10 seconds. What is its acceleration?

a.      9.8 m/s2

b.      0.98m/s2

c.       98m/s2

Answers

Answered by Anonymous
2

u is 0 because the ball is just dropped.

v = 9.8 m/s

acceleration = v-u/t = 9.8-0/10 = 0.98 m/s.

Ans is option B.

Answered by adityaabhisawane
0

Answer:

A

Explanation:

0-98

--------

10 = 9.8

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