Question

if you expect a chemical reaction to produce 4.38 dm3 of oxygen, O2, at 19
oC and 101 kpa, what
would be the volume at 25°C and 101 kpa?​

Answer 1

Answer:

The final volume of the oxygen gas is 4.47$dm^3$ at a temperature of 25°C i.e., 298°K

Given:

In the given chemical reaction of oxygen, the volume of oxygen is changing with temperature, kpa is remain constant in the reaction

The initial temperature of the system = 19°C = 292°K

The initial volume of the oxygen = 4.38

Kpa = 101

After changing the temperature to 25°C

so, the final temperature of the system = 25°C = 298°K

Kpa = 101

To find:

We need to find the final volume of the oxygen at a temperature of 25C i.e., 298k which has 101Kpa.

Explanation:

First, convert the temperature to kelvin,

$T_i$ = 19°C + 273 = 292°K

$T_f$= 25°C + 273 = 298°K

$V_f = V_i \frac{T_f}{T_i}= 4.38 *\frac{298}{292}=4.470 = 4.47dm^3$

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