Question

If you get it then immediatly answer it please fast.

Answer 1

Step-by-step explanation:

$\frac{ {x}^{3} - 64 }{ {x}^{4} + 4 {x}^{3} } = \frac{ {x}^{3} - {4}^{3} }{ {x}^{3} (x + 4)} = \frac{(x - 4)( {x}^{2} + {4}^{2} + 4x)}{ {x}^{3} (x + 4)} \\ \frac{(x - 4)( {x}^{2} + 16 + 4x) }{ {x}^{3} (x + 4)}$