Question

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using remainder and factor theorem factorise the following polynomial :x3 - 19x + 30​

Answer 1

Answer:

Answer is (x-2)(x+5)(x-3)

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Answer 2

Answer:

let us assume x=1

then

1³-19*1+30≠0

now let us assume x=-1

-1³-[19*-1]+30≠0

now let us assume x= 2

2³-19*2+30=0

hence x=2

x-2=0 is one of the factor of x³-19x+30

now

[x³-19x+30/[x-2]

=x²+2x-15

now

x²+2x-15=0

x²+5x-3x-15=0

x[x+5]-3[x+5]=0

[x-3][x+5]=0

x=3 and x=5

hence all three roots of this equation is 2,3,5.

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Step-by-step explanation: