Question

If you have 3 yellow balls, 5 black balls and 3 green balls. If one ball is chosen at random. What is the probability of drawing not a yellow ball.

Answer 1

Answer:

8/11

Step-by-step explanation:

No. of balls here =

YELLOW - 3

BLACK - 5

GREEN - 3

Total no. of balls = 3+5+3 = 11.

Now, to find the probability of not drawing a yellow ball, we can subtract 3 from 11 and write it as the numerator of our fraction.

= 11 - 3 = 8

Now, the reqd. probability = 8/11 (= 0.7272 app.).

Hope it helps.

Pls BRAINLIEST me.

Answer 2

Step-by-step explanation:

let the yellow balls be y1, y2, y3.

let the black ball be b1, b2,b3,b4, b5, .

let the green ball be g1, g2, g3,

n (s)=11

let A be the probability for non-yellow balls

A=(b1,b2,b3,b4,b5,g1,g2,g3)

n (A)=8

p (A)=n (A)/n (s)

• p (A)=8/11