Chemistry, asked by arslansheikh65, 11 months ago

If you have 6.02×10^23 ions of aluminium;how many sulphate ions will be required to prepare AL2(SO4)3?

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Answered by madankumar0802

8

Answer:

If we have 6.02*10*23 (avogadro number) ions of Al then how many sulphate are required to prepare Al2(SO4) 3?

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