Question

If you have 6.02×10^23 ions of aluminium;how many sulphate ions will be required to prepare AL2(SO4)3?
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Answer 1

oh

I'm so sorry bro

all the best for your exams

Answer 2

Answer:

So 3 molecular ions of SO4 for 2 atoms of Al, means 1.5 Avogadro's number molecular ions of SO4 for 1 Avogadro's number atoms of Al that is 9.03 * 10^23 molecular ions of SO4. So 9.03 * 10^23 molecular ions of SO4 will be required.