Question

If you have 6.02×10^23 ions of aluminium;how many sulphate ions will be required to prepare AL2(SO4)3?​

Answer 1

Answer:

Major Dhyan Chand (29 August 1905 – 3 December 1979) was an Indian field hockey player widely regarded as the greatest in the history of the sport.[4] He was known for his extraordinary goal-scoring feats, in addition to earning three Olympic gold medals, in 1928, 1932 and 1936, during an era where India dominated field hockey. His influence extended beyond these victories, as India won the field hockey event in seven out of eight Olympics from 1928 to 1964.

Answer 2

Answer:

3 molecular ions of SO4 for 2 atoms of Al, means 1.5 Avogadro's number molecular ions of SO4 for 1 Avogadro's number atoms of Al that is 9.03 * 10^23 molecular ions of SO4. So 9.03 * 10^23 molecular ions of SO4 will be required.

Hope this helps.

Mark me as brainliest.

Thank you.