Question

If you have 6.02 x 10^23 ions of aluminium; how many sulphate ions will
be required to prepare Al2(SO4)3?

Answer 1

Answer:

So 3 molecular ions of SO4 for 2 atoms of Al, means 1.5 Avogadro's number molecular ions of SO4 for 1 Avogadro's number atoms of Al that is 9.03 * 10^23 molecular ions of SO4. So 9.03 * 10^23 molecular ions of SO4 will be required.

HOPING THIS WILL HELP YOU PLZ MARK AS BRAINLIEST AND FOLLOW ME